SOLUTION: 51 coins. Some are 10$ coins and the rest are 20$ coins. The total of all the coins is 750$. How many of each does he have

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Question 900343: 51 coins. Some are 10$ coins and the rest are 20$ coins. The total of all the coins is 750$. How many of each does he have
Found 2 solutions by ewatrrr, richwmiller:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
20x + 10(51-x) = 750
10x = 750 - 510
10x = 240
x = 24, 20$ coins and 27, 10$coins
And...
480 + 270 = 750

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
x+y=51,
10*x+20*y=750
x=51-y
10*(51-y)+20*y=750
510-10y+20*y=750
10*y=240
y=24
x=51-y
x=27 y=24
check
27+24=51
10*x+20*y=750
10*27+20*24=750
270+480=750
750=750
ok