SOLUTION: Carl has 35 dimes and nickelswhich total $2.55. How many of each type of each coin does he have.

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Carl has 35 dimes and nickelswhich total $2.55. How many of each type of each coin does he have.       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 653645: Carl has 35 dimes and nickelswhich total $2.55. How many of each type of each coin does he have.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = number of nickels
Let +d+ = number of dimes
given:
(1) +n+%2B+d+=+35+
(2) +5n+%2B+10d+=+255+ ( in cents )
---------------------
Multiply both sides of (1) by +5+
and subtract (1) from (2)
(2) +5n+%2B+10d+=+255+
(1) +-5n+-+5d+=+-175+
+5d+=+80+
+d+=+16+
and, since
(1) +n+%2B+d+=+35+
(1) +n+%2B+16+=+35+
(1) +n+=+19+
He has 19 nickels and 16 dimes
check:
(2) +5%2A19+%2B+10%2A16+=+255+
(2) +95+%2B+160+=+255+
(2) +255+=+255+
OK