SOLUTION: Brittany has $9.50 in quarters and dimes. The number of quarters she has is two more than twice the number of dimes. Set up a system of equations and solve for the number of each t
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Brittany has $9.50 in quarters and dimes. The number of quarters she has is two more than twice the number of dimes. Set up a system of equations and solve for the number of each t
Log On
Question 593185: Brittany has $9.50 in quarters and dimes. The number of quarters she has is two more than twice the number of dimes. Set up a system of equations and solve for the number of each type of coin she has.
what i have so far
q=quarters d=dimes
.25q+.10d=9.50
q=2+2d Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Brittany has $9.50 in quarters and dimes.
The number of quarters she has is two more than twice the number of dimes.
Set up a system of equations and solve for the number of each type of coin she has.
what i have so far
q=quarters d=dimes
.25q+.10d=9.50
q = 2+2d
Now all you have to do is replace q with (2d+2) in the 1st equation
.25(2d+2) + .10d = 9.50
.50d + .5 + .10d = 9.50
.50d + .10d = 9.50 - .50
.60d = 9.00
d =
d = 15 dimes
:
I know you can find the number of quarters now. Check your solutions in the 1st equation.
