Question 592183: Diane has $1.80 in dimes and nickels. She has a total of 22 coins. How many of each kind does she have? Found 4 solutions by htmentor, stanbon, MNH98, MathTherapy:Answer by htmentor(1343) (Show Source):
You can put this solution on YOUR website! Diane has $1.80 in dimes and nickels. She has a total of 22 coins. How many of each kind does she have?
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Let d = the number of dimes
Then 22 - d = the number of nickels
The equation for the total amount is:
5(22-d) + 10d = 180
110 - 5d + 10d = 180
5d = 70
d = 14
So the number of dimes is 14 and the number of nickels is 8.
You can put this solution on YOUR website! Diane has $1.80 in dimes and nickels. She has a total of 22 coins. How many of each kind does she have?
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Equations:
Quantity: d + n = 22 coins
Value: 10d +5n = 180
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Multiply thru the Quantity Eq. by 5 to get:
5d + 5n = 110
10d + 5n = 180
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Subtract and solve for "d":
5d = 70
d = 14 (# of dimes)
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Solve for "n":
d + n = 22
14 + n = 22
n = 8 (# of nickels)
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Cheers,
Stan H.
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