SOLUTION: Hi i have a question that is really baffaling me.Can someone please help me?
A jar of change has $90.15 in it.There are six less dimes than twice the nickels.There are three m
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: Hi i have a question that is really baffaling me.Can someone please help me?
A jar of change has $90.15 in it.There are six less dimes than twice the nickels.There are three m
Log On
Question 143545: Hi i have a question that is really baffaling me.Can someone please help me?
A jar of change has $90.15 in it.There are six less dimes than twice the nickels.There are three more quarters than 4 times the amount of nickels.How many nickels,dimes,and quarters are in the jar?(There are no pennies.)Thanks!! Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! 90.15
Let n be the number of nickels
Dimes = 2n - 6 --> d = 2n - 6
Quarters = 4n + 3 --> q = 4n +3