SOLUTION: HI please help me with this A parking meter accepts only Quarters and dollars. If there are 31 coins and a value of $ 20.50 how many quarters and dollars are there. thanks f

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Question 118146: HI
please help me with this
A parking meter accepts only Quarters and dollars. If there are 31 coins and a value of $ 20.50 how many quarters and dollars are there.
thanks for any help coming my way
Found 2 solutions by scott8148, ankor@dixie-net.com:
Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website!
let x=quarters, so 31-x=dollars ___ working in cents to avoid decimals

x(25)+(31-x)(100)=2050 ___ 25x+3100-100x=2050 ___ -75x=-1050

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
A parking meter accepts only Quarters and dollars. If there are 31 coins and a value of $ 20.50 how many quarters and dollars are there.
:
let q = no. of quarters,
:
let d = no. of dollar coins
:
We can make two simple equations from the given information
The number of coins equation (it says there are 31 coins):
q + d = 31
:
It says the value of the coins is 20.50
.25g + 1d = 20.50
:
1d and d are the same so use elimination
q + d = 31
.25q +d = 20.50
------------------subtracting eliminates d, find q
.75q +0 = 10.50
q = 10.50/.75
q = 14 quarters
:
That would leave us:
31 - 14 = 17 dollar coins
:
Check that in our value equation
.25(14) + 1(17) =
3.50 + 17 = 20.50, confirms our solutions
:
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