SOLUTION: Tanner has $4.25 in nickels and quarters. Suppose he has 19 more nickels than quarters. (Let x represent the number of quarters. Complete the table below such that each entry is in

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: Tanner has $4.25 in nickels and quarters. Suppose he has 19 more nickels than quarters. (Let x represent the number of quarters. Complete the table below such that each entry is in      Log On

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Question 1154515: Tanner has $4.25 in nickels and quarters. Suppose he has 19 more nickels than quarters. (Let x represent the number of quarters. Complete the table below such that each entry is in terms of x.
Found 2 solutions by josmiceli, greenestamps:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = the number of quarters
+x+%2B+19+ = the number of nickels
--------------------------------------------
+5%2A%28+x+%2B+19+%29+%2B+25x+=+425+ ( the units are cents )
+5x+%2B+95+%2B+25x+=+425+
+30x+=+330+
+x+=+11+
and
+x+%2B+19+=+30+
----------------------
Tanner has 30 nickels and 11 quarters
----------------------
I don't have the table, so you
have to use the equation to
fill in the table

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

  # of quarters  # of nickels  total value
        x             x+19       (cents)
 ------------------------------------------
        0              19          95
        1              20         125
        2              21         155
       ...
       10              29         395
       11              30         425

Of course, in practice you wouldn't solve the problem by making a table; you could use basic algebra.

However, the table shows how I would solve the problem without algebra, using logical reasoning.

(1) The 19 "extra" nickels have a value of 95 cents.
(2) adding one more quarter and one more nickel (to keep the number of nickels 19 more than the number of quarters) adds 30 cents to the total.
(3) 95 cents is 330 cents short of the actual total of 425 cents. The number of times I have to add one quarter and one nickel to make those other 330 cents is 330/30 = 11.

So I have 11 quarters and 11+19 = 30 nickels