SOLUTION: a vending machine has 4.00 in nickels and.dimes if the number of dimes is 5 less than twice the number of nickels how many of each coin is there?

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Question 1100081: a vending machine has 4.00 in nickels and.dimes if the number of dimes is 5 less than twice the number of nickels how many of each coin is there?
Answer by ikleyn(53763)   (Show Source):
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d = 2n - 5 (1) (counting coins) 5n + 10d = 400 (2) (counting cents) Substitute (1) into (2). You will get 5n + 10*(2n-5) = 400, 5n + 20n - 50 = 400 ====> 25n = 400 + 50 = 450 ====> n = = 18. Answer. 18 nickels and 2*18-5 = 31 dime. Check. 18*5 + 31*10 = 400. ! Correct !

There is entire bunch of lessons on coin problems
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    - More Coin problems
    - Solving coin problems without using equations
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    - Three methods for solving standard (typical) coin word problems
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    - OVERVIEW of lessons on coin word problems
in this site.

You will find there the lessons for all levels - from introductory to advanced,
and for all methods used - from one equation to two equations and even without equations.

Read them and become an expert in solution of coin problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Coin problems".

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Free of charge online textbook in ALGEBRA-I
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