SOLUTION: Justin has $4.75 in quarters, dimes, and nickels. If he has a total of 27 coins and he has twice as many dimes as nickels, how many of each coin does he have?

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Question 1095529: Justin has $4.75 in quarters, dimes, and nickels. If he has a total of 27 coins and he has twice as many dimes as nickels, how many of each coin does he have?
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
he has twice as many dimes as nickels,

Let N = number of nickels
Then 2N = the number of dimes.

he has a total of 27 coins 
        
 
Number of quarters =  27 -    N    -    2N 
Number of quarters =  27 - 3N

Justin has $4.75 in quarters, dimes, and nickels



   0.25N   +  0.10(2N) + 0.05(27-3N) =  4.75

Move the decimals two places right in each term:

     25N   +    10(2N) +    5(27-3N) =   475

Simplify and solve that for N, the number of nickels, 
then substitute what you get for N in:

2N = the number of dimes
27 - 3N = the number of quarters

Edwin