SOLUTION: Hannah's cash box contains $160. made up of quarters($0.25), loonies($1), and toonies($2). How many quarters, loonies and toonies are in the box if the number of loonies is four mo
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Question 1095409: Hannah's cash box contains $160. made up of quarters($0.25), loonies($1), and toonies($2). How many quarters, loonies and toonies are in the box if the number of loonies is four more than three-sevenths the number of toonies, and the number of quarters is eight times the number of loonies and toonies together? Answer by greenestamps(13200) (Show Source):
You can put this solution on YOUR website! With the given information that the number of loonies is 4 more than 3/7 the number of toonies, I would start my algebraic solution with...
let 7x = number of toonies
then 3x+4 = number of loonies
Of course you could define your variables differently and work with fractions; but I prefer to make my work easier by avoiding fractions if possible.
With that start, we know the number of quarters is 8 times the number of loonies and toonies together:
8(10x+4) = 80x+32 = number of quarters
Now we have all the numbers in terms of a single variable. So write and solve the equation that says the total value of the coins is $160:
number of toonies: 7x = 28
number of loonies: 3x+4 = 16
number of quarters: 80x+32 = 352
