SOLUTION: Heidi and Micah have 51 dimes and nickles. If the value of the coins is $4.10, how many coins of each type were there?

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Question 1079258: Heidi and Micah have 51 dimes and nickles. If the value of the coins is $4.10, how many coins of each type were there?
Found 2 solutions by Fombitz, MathTherapy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.N%2BQ=51
and
5N%2B25Q=410
2.N%2B5Q=82
Subtract 1 from 2,
N%2B5Q-N-Q=82-51
4Q=31
Check your problem setup.
Q and N are not integers which they need to be.
Please repost.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!
Heidi and Micah have 51 dimes and nickles. If the value of the coins is $4.10, how many coins of each type were there?
No need to repost!!
Correct answer: