SOLUTION: A can contains 3 tennis balls tightly packed. Each ball has a diameter of 2.5 inches. How much greater is the circumference of the can than the height of the can?
Algebra ->
Volume
-> SOLUTION: A can contains 3 tennis balls tightly packed. Each ball has a diameter of 2.5 inches. How much greater is the circumference of the can than the height of the can?
Log On
Question 993240: A can contains 3 tennis balls tightly packed. Each ball has a diameter of 2.5 inches. How much greater is the circumference of the can than the height of the can?
You can put this solution on YOUR website! Hi there,
Each ball has a diameter of 2.5 inches
Circumference = Pi x diameter
Circumference = Pi x 2.5
Circumference = 7.85 inches (2 decimal places)
Height = 3 x 2.5
Height = 7.5 inches
Circumference - Height
7.85 - 7.5 = 0.35 inches
Hope this helps :-)