SOLUTION: A cyclist rode 24 miles in three hours. She returned in 12 hours against the wind. Find the rate of the cyclist without wind and the rate of the wind.

Algebra ->  Customizable Word Problem Solvers  -> Unit conversion -> SOLUTION: A cyclist rode 24 miles in three hours. She returned in 12 hours against the wind. Find the rate of the cyclist without wind and the rate of the wind.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 278019: A cyclist rode 24 miles in three hours. She returned in 12 hours against the wind. Find the rate of the cyclist without wind and the rate of the wind.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
3*(c+w)=24
12*(c-w)=3c+3w
12c-12w=3c+3w
9c=15w
3c=5w
3c+3w=24
5w+3w=24
8w=24
wind =3 mph
3c=5w
3c=15
cyclist=5 mph without wind
check
12(5-3)=24
12*2=24
ok
3*(5+3)=24
3*8=24
24=24
ok