SOLUTION: I need help finding the solutions for this question. Find all solutions in the interval [0,2pi ] for: sinx *cosx - (1/2)cosx =0
Algebra ->
Trigonometry-basics
-> SOLUTION: I need help finding the solutions for this question. Find all solutions in the interval [0,2pi ] for: sinx *cosx - (1/2)cosx =0
Log On
Question 961635: I need help finding the solutions for this question. Find all solutions in the interval [0,2pi ] for: sinx *cosx - (1/2)cosx =0 Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! I need help finding the solutions for this question. Find all solutions in the interval [0,2pi ] for: sinx *cosx - (1/2)cosx =0
***
cosx(sinx-1/2)=0
cosx=0
x=π/2, 3π/2
or
sinx=1/2
x=π/6, 5π/6 (In quadrants I and II where sin>0)
(