Question 872813: Find the exact values of the six trigonometric functions of t if p= (-1/3, 2 square root of 2 over 3) is the point on the unit circle that corresponds to t
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the exact values of the six trigonometric functions of t if p= (-1/3, 2 square root of 2 over 3) is the point on the unit circle that corresponds to t
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x = -1/3
y = 2sqrt(2)/3
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r = sqrt[(1/3)^2 + (2sqrt(2)/3)^2] = sqrt[(1/9)+(8/9)] = 1
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sin = x/r = -1/3
cos = y/r = 2sqrt(2)/3
tan = y/x = -1/2sqrt(2)
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csc, sec, and cot are the inverse of sin, cos, and tan
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Cheers,
Stan H.
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