Question 864231: "Find sin theta/2 given that sin theta=-15/17,
where pi is less than theta is less than 3pi/2."
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! "Find sin theta/2 given that sin theta=-15/17,
where pi is less than theta is less than 3pi/2."
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Form:: sin(x/2) = sqrt[(1-cos(x))/2
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Since sin = y/r, y = -15 ; r = 17
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In QIII x is negative.
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x = -sqrt[17^2-15^2] = -8
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Then cos(t) = -8/17
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Ans: sin(t/2) = sqrt[(1-(-8/17))/2] = sqrt[25/34] = 5/sqrt(34)
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Cheers,
Stan H.
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