SOLUTION: Find the equaiton in standard form of the ellipse with center at (4,2) foci (1,2) and (7,2) and minor axis of length 10.

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Question 857858: Find the equaiton in standard form of the ellipse with center at (4,2) foci (1,2) and (7,2) and minor axis of length 10.
Answer by lwsshak3(11628) About Me  (Show Source):
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Find the equation in standard form of the ellipse with center at (4,2) foci (1,2) and (7,2) and minor axis of length 10.
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Given ellipse has a horizontal major axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1,a>b, (h,k)=coordinates of center
center: (4,2)
c=3 (from center to foci)
c^2=9
length of minor axis=10=2b
b=5
b^2=25
c^2=a^2-b^2
a^2=c^2+b^2=9+25=34
Equation of given ellipse:
%28x-4%29%5E2%2F34%2B%28y-2%29%5E2%2F25=1