SOLUTION: Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf 5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta) thanks in adv

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf 5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta) thanks in adv      Log On


   

Question 857628: Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf

5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta)
thanks in advance
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following equation in the interval 0 < theta < 2pi. Give your final answers in radians correct to 3 sf
5*sin^2(theta)-3 =2sin(theta)+4cos^2(theta)
5sin%5E2%28x%29-3=2sin%28x%29%2B4cos%5E2%28x%29
5sin%5E2%28x%29-3=2sin%28x%29%2B4%281-sin%5E2%28x%29%29
5sin%5E2%28x%29-3=2sin%28x%29%2B4-4sin%5E2%28x%29
9sin%5E2%28x%29-2sin%28x%29-7
(9sinx+7)(sinx-1)=0
..
9sinx+7=0
sinx=-7/9
x≈0.891
or
sinx-1=0
sinx=1
x=π/2