SOLUTION: α and β are quadrant I angles with cos(α) = 15/17 and csc(β) = 41/9 Find tan(α - β).

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Question 849840: α and β are quadrant I angles with cos(α) = 15/17 and csc(β) = 41/9
Find tan(α - β).
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
α and β are quadrant I angles with
cos(α) = 15/17
Therefore sin(alpha) = sqrt[17^2-15^2]/17 = 8/17
Then tan(alpha) = 8/15
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and csc(β) = 41/9
sin(Beta) = 9/41
So, cos(Beta) = sqrt[41^2-9^2]/41 = 40/41
Then tan(Beta) = 9/41
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Find tan(α - β) = [tan(a)-tan(b)]/[1+tan(a)tan(b)
Note: Just plug in the numbers.
Cheers,
Stan H.
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