Question 813641: When a vendor prices key chains at $5 each, she sells 210 key chains. For each $1 she raises the price, she sells 10 fewer key chains. USE AN EQUATION to determine what she should charge to maximize her revenue from sales.
Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! use the revenue equation:
r = p * n
where
p = price per item
n = number of items sold
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because we know that changing the price (p) also changes the number sold (n), we need to introduce a variable to the revenue equation to measure the changes in p and n.
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so just make up a variable, call it x, such that:
p + x means a one dollar price increase and
p - x means a one dollar price decrease and
n + x means a one item number-sold increase and
n - x means a one item number-sold decrease
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for each $1 price increase (p + x) there are 10 fewer items sold (n - 10x), so:
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r = (p + x) * (n - 10x)
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we know that at $5 per item, she sells 210 items, so:
r = (5 + x) * (210 - 10x)
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r = (5 + x) * (210 - 10x)
r = 1050 - 50x + 210x - 10xx
r = -10xx + 160x + 1050
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the above quadratic equation is in standard form, with a=-10, b=160, and c=1050
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to solve the quadratic equation, plug this:
-10 160 1050
into this: https://sooeet.com/math/quadratic-equation-solver.php
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Answer 1:
the quadratic equation has a maximum at: ( x=8, r=1690 ), so:
maximum revenue is $1690
when price per item is $8
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