SOLUTION: How can I find the arccos of 1, with all possible answers?

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Question 807759: How can I find the arccos of 1, with all possible answers?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
ANSWER:
The function arccos%28x%29 is defined as the angle theta that satisfies cos%28theta%29=x and 0%3C=theta%3C=pi
(and we measure angles in radians, not degrees).
If the question is finding the angle theta such that cos%28theta%29=1,
then there are infinite answers,
so you have to give them as theta+=2k%2Api in radians,
(or theta+=k%2A360%5Eo if you measure angles in degrees),
where k is any integer.
However, to define arccos%28x%29 as a function,
we choose just the most trivial of those answers, theta=0 ,
so arccos%281%29=0 (just one answer).

EXPLANATION AND MORE:
The drawing below shows the unit circle and an angle, theta=AOB , in standard position.
theta+=30%5Eo or theta=pi%2F6 depending on the units you use for angles.
Angles are measured as turns counterclockwise from ray OA to ray OB.
It is a useful way to define angles for technical issues,
such as stating the angle a control knob has to be turned to get to the desired position.
You start with OB coinciding with OA and theta=0.
As you turn OB around O, you eventually go one full turn and get back to OA,
and that turn is considered to be 360%5Eo or 2pi.
After another turn, the angle would be 720%5Eo or 4pi
I say that the angle theta in my drawing is 30%5Eo ,
because I say that I just turned from OA to OB the shortest possible way.
If I said that I turned a little over 2 turns clockwise on my way from OA to OB, then it would be
theta=720%5Eo%2B30%5Eo=750%5Eo
Cosine is defined as the x-coordinate of point B, while sine is the y-coordinate.
In my drawing, those coordinates are
x%5BB%5D=cos%28theta%29=sqrt%283%29%2F2=about0.866 and
y%5BB%5D=sin%28theta%29=1%2F2=0.5 .
There is another point in the circle (point C) with the same x-coordinate,
as there is another point (point D) with the same y-coordinate.

It is obvious that the only point in the circle with x=1 is point A,
so for cos%28theta%29=1 we get infinite answers, but just one answer per turn,
and the answers are all 2pi or 360%5Eo apart.
The same thing happens for x=-1 and arccos%28-1%29 at the other extreme of the range of x values for the circle.
For values in between those extremes, such as
sqrt%283%29%2F2=about0.866 ,
there are twice as many answers,
because there are twice as many points with that x-coordinate.
x%5BB%5D=sqrt%283%29%2F2=x%5BC%5D so cos%28AOB%29=sqrt%283%29%2F2=cos%28AOC%29
and we can say AOC=-30%5Eo or AOC=-pi%2F6 if we choose the simplest way to define those angles.
For the infinite answers to cos%28theta%29=sqrt%283%29%2F2 ,
we have to express all the coterminal angles (that differ from AOB and AOC by a whole number of turns) as
theta=2k%2Api+%2B-+pi%2F6 (or theta=k%2A360%5Eo+%2B-+30%5Eo if we use degrees) for any integer k .