SOLUTION: GIven Cos teta = -square root of 3 / 2 ; 180 < teta < 270 Find exact value of A) Sin of teta b) Tan of tera

Algebra ->  Trigonometry-basics -> SOLUTION: GIven Cos teta = -square root of 3 / 2 ; 180 < teta < 270 Find exact value of A) Sin of teta b) Tan of tera      Log On


   

Question 799155: GIven Cos teta = -square root of 3 / 2 ; 180 < teta < 270
Find exact value of A) Sin of teta
b) Tan of tera
Answer by Alan3354(69443) About Me  (Show Source):
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GIven Cos teta = -square root of 3 / 2 ; 180 < teta < 270
Find exact value of
A) Sin of teta
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sin%28t%29+=+sqrt%281+-+cos%5E2%28t%29%29
= sqrt%281+-+3%2F4%29+=+sqrt%281%2F4%29+=+1%2F2
sin(t) = -1/2 in Q3
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b) Tan of tera
tan = sin/cos = (-1/2)/(-sqrt(3)/2)
= 1/sqrt(3)
= sqrt(3)/3