Question 755989: if tan theta= -13/12 where theta is in 2nd quadrant find remaing trigonometric ratios Found 2 solutions by solver91311, priyanka kothandaraman:Answer by solver91311(24713) (Show Source):
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tan theta = sin theta/cos theta
So
sin/cos=-13/12
12sin theta=-13cos theta
144sin^2theta=169^2theta
but,
cos^2theta=1-sin^2theta
144sin^2theta=169-169sin^2theta
sin theta=169/313
sin theta=13/root313
=13root313/313
Note: save the unrationalized denominator form for ease of taking the reciprocal later.
Do in the same fashion giving you three of the six functions. Then, the other functions are just reciprocals: