Question 745905: If sin θ =3/4 and θ is in quadrant II, find tan?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If sin θ =3/4 and θ is in quadrant II, find tan?
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sin = y/r = 3/4 implies that y = 3 and r = 4.
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Solve for "x" in Q(II)
Note: x is negative in QII:
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-x = sqrt[r^2-y^2] = sqrt[4^2-3^2] = sqrt(7)
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x = -sqrt(7)
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tan = y/x = -3/sqrt(7) or (-3/7)sqrt(7)
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Cheers,
Stan H.
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