SOLUTION: how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being
2*radical 3/2. Any help wo
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-> SOLUTION: how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being
2*radical 3/2. Any help wo
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Question 735749: how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being
2*radical 3/2. Any help would be greatly appreciated :) Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! how do you find sin600 using the double angle identity.the farthest I had gotten was sin(2*600)=2sin(600)cos(600). Cos 600 being -1/2 and sin 600 being
2*radical 3/2. Any help would be greatly appreciated :)
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sin(600) = 2sin(300)cos(300) **** not sin(600)....
= 2*(-sqrt(3)/2)*(1/2)
=
