SOLUTION: how to solve sin(x)=-1/2 in the interval [0,2pi]

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Question 725975: how to solve sin(x)=-1/2 in the interval [0,2pi]
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
how to solve sin(x)=-1/2 in the interval [0,2pi]
sinx=-1/2
x=7π/6, 11π/6 (in quadrants III and IV where sin<0)