SOLUTION: I need to prove this identity tan^2theta-sin^2theta = tan^2thetasin^2theta
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Question 714760
:
I need to prove this identity
tan^2theta-sin^2theta = tan^2thetasin^2theta
Answer by
josgarithmetic(39620)
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You can
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On the left side we can say (sin^2)/(cos^2)-sin^2
=sin^2/cos^2-(sin^2*cos^2)/cos^2
=(sin^2 *(1-cos^2))/cos^2
=
To finish this, use
in the form of
, and perform the substitution into that last step above.