SOLUTION: (sin^2x+cos^2x)/ cosx = secx

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Question 694640: (sin^2x+cos^2x)/ cosx = secx
Answer by sachi(548) (Show Source):
You can put this solution on YOUR website!
the question is actually (sin^2x+cos^2x)/cosx=secx
or 1/cosx=secx (as sin^2x+cos^2x=1 always)