SOLUTION: A belt connects two pulleys with a radio 3in(point B) and 5in (point C). The velocity of point A on the pelt is 10ft/sec. What is the linear velocity (ft/sec) and the angular veloc

Algebra ->  Trigonometry-basics -> SOLUTION: A belt connects two pulleys with a radio 3in(point B) and 5in (point C). The velocity of point A on the pelt is 10ft/sec. What is the linear velocity (ft/sec) and the angular veloc      Log On


   

Question 694182: A belt connects two pulleys with a radio 3in(point B) and 5in (point C). The velocity of point A on the pelt is 10ft/sec. What is the linear velocity (ft/sec) and the angular velocity (rad/sec) for point B?What is the linear velocity (ft/sec) and the angular velocity (rad/sec) for point C?
Hint: every point on the belt is moving at the same speed.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
A belt connects two pulleys with a radius 3in(point B) and 5in (point C). The velocity of point A on the belt is 10ft/sec. What is the linear velocity (ft/sec) and the angular velocity (rad/sec) for point B?What is the linear velocity (ft/sec) and the angular velocity (rad/sec) for point C?
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At point B (3in pulley)
Convert linear velocity to angular velocity
circumference=π*diameter=π*6 in=π/2 ft
10 ft/sec*rev/π/2 ft*2π rad/rev
10*2*2 rad/sec=40 rad/sec
...
At point B (3in pulley)
Convert linear velocity to angular velocity
circumference=π*diameter=π*10 in=π*5/6 ft=5π/6 ft
10 ft/sec*rev/5π/6 ft*2π rad/rev
(10*6*2)/5 rad/sec=24 rad/sec
..
linear velocity is constant at all points on the belt at 10 ft/sec