SOLUTION: For 0 < theta < pi/3, solve 8 sin^3 (theta) - 6 sin (theta) + 1 = 0

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Question 681577: For 0 < theta < pi/3, solve
8 sin^3 (theta) - 6 sin (theta) + 1 = 0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
For 0 < theta < pi/3, solve
8 sin^3 (theta) - 6 sin (theta) + 1 = 0
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Factor:
(4sin(theta)-1)(2sin(theta)-1) = 0
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sin(theta) = 1/4 or sin(theta) = 1/2
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theta = sin^-1(1/4) = 0.2450 or theta = sin^-1(1/2) = 0.4636
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Cheers,
Stan H.
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