SOLUTION: state the amplitude, period, domain range and phase shift of the cycles
a) y=sin(3x-180)
when i graphed this function it turned into the base graph and then when i found the
Algebra ->
Trigonometry-basics
-> SOLUTION: state the amplitude, period, domain range and phase shift of the cycles
a) y=sin(3x-180)
when i graphed this function it turned into the base graph and then when i found the
Log On
Question 610583: state the amplitude, period, domain range and phase shift of the cycles
a) y=sin(3x-180)
when i graphed this function it turned into the base graph and then when i found the period i got 120 degrees and the phase shift was 60 derees so my graph doesnt match my answers :( Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! state the amplitude, period, domain range and phase shift of the cycles
a) y=sin(3x-180)
when i graphed this function it turned into the base graph and then when i found the period i got 120 degrees and the phase shift was 60
---------------------------------
Form: y = a*sin(bx-c)+d
---
Your problem:
a = 1 ; b = 3 ; c = 180 ; d = 0
-----
amplitude = |a| = |1| = 1
period = (360/b) = 360/3 = 120
phase shift = c/b = 180/3 = 60
====================================
domain: All Real Numbers
range: -1<= y <=1
====================================
Cheers,
Stan H.