SOLUTION: Solve the equation on the interval [0,2pi) 2 cos^2 x + sin x -2 = 0

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the equation on the interval [0,2pi) 2 cos^2 x + sin x -2 = 0      Log On


   

Question 597421: Solve the equation on the interval [0,2pi)
2 cos^2 x + sin x -2 = 0
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the equation on the interval [0,2pi)
2 cos^2 x + sin x -2 = 0
------
2(1-sin^2) + sin -2 = 0
----
2-2sin^2+sin -2 = 0
2sin^2 - sin = 0
sin(x)(2sin(x)-1) = 0
sin(x) = 0 or sin(x) = 1/2
x = 0 or pi or 2pi or pi/6 or (5/6)pi
=============================================
Cheers,
Stan H.