SOLUTION: Please help me solve these identities! tan[cos^-1(-square root of 3/2)] and the answer in the book is -square root of 3/3.
cos(-theta)-cos(theta)=? i think its zero?? any help is
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-> SOLUTION: Please help me solve these identities! tan[cos^-1(-square root of 3/2)] and the answer in the book is -square root of 3/3.
cos(-theta)-cos(theta)=? i think its zero?? any help is
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Question 597047: Please help me solve these identities! tan[cos^-1(-square root of 3/2)] and the answer in the book is -square root of 3/3.
cos(-theta)-cos(theta)=? i think its zero?? any help is appreciated. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Please help me solve these identities! tan[cos^-1(-square root of 3/2)] and the answer in the book is -square root of 3/3.
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tan[cos^-1(√3/2)]
cos^-1(√3/2 is an angle whose cos=√3/2
This angle is π/6
so tan[cos^-1(√3/2)]
=tan π/6=√3/3
(