SOLUTION: For each, on the same set of axes graph for 0<(or equal to)x<(or equal to)2pi. Must show a chart with the appropriate radian values: a. y=sinx and y=sin(x-1) b. y=sinx and y=sin

Algebra ->  Trigonometry-basics -> SOLUTION: For each, on the same set of axes graph for 0<(or equal to)x<(or equal to)2pi. Must show a chart with the appropriate radian values: a. y=sinx and y=sin(x-1) b. y=sinx and y=sin      Log On


   



Question 596049: For each, on the same set of axes graph for 0<(or equal to)x<(or equal to)2pi. Must show a chart with the appropriate radian values:
a. y=sinx and y=sin(x-1)
b. y=sinx and y=sinx-1
c. explain the difference and how it impacts the transformations

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
For each, on the same set of axes graph for 0<(or equal to)x<(or equal to)2pi. Must show a chart with the appropriate radian values:
a. y=sinx and y=sin(x-1)
b. y=sinx and y=sinx-1
c. explain the difference and how it impacts the transformations
**
y=sinx
This is the basic sin function with following coordinates for 0-2π:
(0,0), (π/2,1), (π,0), (3π/2,-1), (2π,0)
..
y=sin(x-1)
This shifts the basic sin function one unit to the right with following coordinates for 0-2π:
(1,0), (π/2+1,1), (π+1,0), (3π/2+1,-1), (2π+1,0)
y-intercept:
x=0
sin(-1)≈0.841
..
y=sinx-1
This shifts the basic sin function one unit up with following coordinates for 0-2π:
(0,-1), (π/2,0), (π,-1), (3π/2,-2), (2π,-1)
y-intercept:
x=0
sinx-1=0-1=-1
..
You now have the information you need to graph given functions. Sorry, I don't have the means to draw the graphs for you.