SOLUTION: Solve the equation on the interval [0,2pi). sin(x)sec(x)=2 sin(x)

Algebra ->  Trigonometry-basics -> SOLUTION: Solve the equation on the interval [0,2pi). sin(x)sec(x)=2 sin(x)      Log On


   

Question 590098: Solve the equation on the interval [0,2pi).
sin(x)sec(x)=2 sin(x)
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
          sin(x)sec(x) = 2sin(x)
sin(x)sec(x) - 2sin(x) = 0
    sin(x)[sec(x) - 2] = 0

sin(x) = 0;    sec(x) - 2 = 0

     x = 0,p       sec(x) = 2
                   cos(x) = 1%2F2
                        x = pi%2F3, 5pi%2F3

Edwin