SOLUTION: TANA+COTB/COTA+TANB=TANA+COTB

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Question 470938: TANA+COTB/COTA+TANB=TANA+COTB
Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
TANA+COTB/COTA+TANB=TANA+COTB
You didn't put in any parentheses to show where the
numerators and denominators begin and end.

However this equation cannot be an identity regardless
of where the parentheses should go -- because
suppose A=45° and B=45°.  Then 

tan(A) = tan(B) = cot(A) = cot(B) = 1 

The above becomes:

TANA+COTB/COTA+TANB=TANA+COTB

           1+1/1+1 = 1+1

Theis is no way to put parentheses in the left side to
make that equation true.

Edwin