SOLUTION: Factorise each of the following over C
a) f(z)=z^3+z^2+2z-4
b)g(z)= z^3+(2-i)z^2-z-2+i
i tried solving them as:
a) the factor of f(z) is (z-1), then do the long division and
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-> SOLUTION: Factorise each of the following over C
a) f(z)=z^3+z^2+2z-4
b)g(z)= z^3+(2-i)z^2-z-2+i
i tried solving them as:
a) the factor of f(z) is (z-1), then do the long division and
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Question 470838: Factorise each of the following over C
a) f(z)=z^3+z^2+2z-4
b)g(z)= z^3+(2-i)z^2-z-2+i
i tried solving them as:
a) the factor of f(z) is (z-1), then do the long division and the answer will be (z^2+2z+4) and so
f(z)=(z-1)(z^2+2z+4)
= (z-1)(z+1)^2 -1+4 <<< got stuck, how can i complete?
b)the factor of g(z) is (z+2+i), then do the long division and the answer will be z^2+1 and so
g(z)= (z+2-i)(z^2-1) <<<< how can i complete?
Thanks Answer by solver91311(24713) (Show Source):
