SOLUTION: how do you graph the cosine function with a phase shift of + 5pi / 6.

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Question 470024: how do you graph the cosine function with a phase shift of + 5pi / 6.
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
how do you graph the cosine function with a phase shift of + 5pi / 6
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Standard form for cosine function: y=Acos(Bx-C), with A=amplitude, Period=2π/B, Phase-shift=C/B.
For given cosine function, I will assume A=1, B=1 with given phase shift, +5π/6, and graph it for one period.
Equation: y=cos(x+5π/6)
Period: 2π/1=2π
1/4 Period=π/2
Phase-shift: 5π/6 (left)
..
Graphing:
On the x-axis (radians), make the first tick mark at -5π/6.
Moving to the right, make 4 more tick marks spaced 1/4 period apart, that is, at:
-2π/6, π/6, 4π/6, 7π/6
Now, you have the following points to plot: (-5π/6,1), (-2π/6,0), (π/6,-1), (4π/6,0), (7π/6,1)
To complete the graph, find the y-intercept at x=0
y-int=cos(5π/6)=-.866
see graph below as a visual check on answers
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+graph%28+300%2C+300%2C+-5%2C+5%2C+-2%2C+2%2C+cos%28x%2B5%2A3.14%2F6%29%29+