SOLUTION: Using the Intermediate Value Theorem, show that the function f has a zero between a and b. f(x)=x^3+4x^2-8x-10 a=-6, b=-5 what is f(-6)? what is f(-5)? is there a zero b

Algebra ->  Trigonometry-basics -> SOLUTION: Using the Intermediate Value Theorem, show that the function f has a zero between a and b. f(x)=x^3+4x^2-8x-10 a=-6, b=-5 what is f(-6)? what is f(-5)? is there a zero b      Log On


   

Question 458901: Using the Intermediate Value Theorem, show that the function f has a zero between a and b.
f(x)=x^3+4x^2-8x-10 a=-6, b=-5
what is f(-6)?
what is f(-5)?
is there a zero between x=-6 and x=-5
Answer by richard1234(7193) About Me  (Show Source):
You can put this solution on YOUR website!
f(-6) = -34
f(-5) = 5

The function is continuous, so there is a zero between -6 and -5.