Question 287610: I have a question regarding the values of sin B and csc B. For example, if Sin B= 5 squrt 2/5 squrt 3, how would you find the value of csc B? I know that csc= r/y and that sin = opp/hyp. The Pythagorean Theorem states that a^2 + b^2 = c^2. So, would this be correct if I substitute in the problems as: (5 squrt 2)^2 + b^2 = (5 squrt 3)^2? I am not of the answer though; I found it was either sqrt 6/3 or sqrt 6/2...however, I am not completely sure if I solved correctly. Could you please help me in finding the answer?
Thank you!
Answer by mananth(16946)   (Show Source):
You can put this solution on YOUR website! I have a question regarding the values of sin B and csc B. For example, if Sin B= 5 squrt 2/5 squrt 3, how would you find the value of csc B?
sin B= sqrt 2/5 sqrt3
sin b= sqrt 2/5 * 3
sin b= sqrt 6/5
csc b = 1/ sinb
csc b = 1/sqrt (6/5)
= 0.912
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