SOLUTION: Help me pleaseOn a forward somersault Pats height is y meters above the water x seconds after she leaves the diving board, where y= -5(x-6)^2 + 3.8. Pats maximum height above water

Algebra ->  Trigonometry-basics -> SOLUTION: Help me pleaseOn a forward somersault Pats height is y meters above the water x seconds after she leaves the diving board, where y= -5(x-6)^2 + 3.8. Pats maximum height above water      Log On


   



Question 184755: Help me pleaseOn a forward somersault Pats height is y meters above the water x seconds after she leaves the diving board, where y= -5(x-6)^2 + 3.8. Pats maximum height above water is
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Pats height is y meters above the water x seconds after she leaves the diving board, where y= -5(x-6)^2 + 3.8. Pats maximum height above water is
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Vertex form y = a(x-h)^2 + k
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The vertex is (6,3.8)
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The maximum height was 3.8 meters.
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graph%28400%2C300%2C-10%2C10%2C-10%2C10%2C-5%28x-6%29%5E2%2B3.8%29
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Cheers,
Stan H.