SOLUTION: Solve 8sin0(with a line through it)+4=0, where 0(with a line through it) is any real number of radians. I worked it out to 0(with a line through it)= 7pi/6+
2(pi)n and 11pi/6+2(p
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-> SOLUTION: Solve 8sin0(with a line through it)+4=0, where 0(with a line through it) is any real number of radians. I worked it out to 0(with a line through it)= 7pi/6+
2(pi)n and 11pi/6+2(p
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Question 184041This question is from textbook saxon algebra 2
: Solve 8sin0(with a line through it)+4=0, where 0(with a line through it) is any real number of radians. I worked it out to 0(with a line through it)= 7pi/6+
2(pi)n and 11pi/6+2(pi)n. Am I correct? This question is from textbook saxon algebra 2
Absolutely correct, though you might have added the little nicety of saying that n is an integer.
By the way, you were trying to describe the Greek capital letter Theta . That is just a common convention used for trigonometric expressions. In fact, any variable will do to convey the same message, so next time just write .
