You can put this solution on YOUR website! y^2+x^2+9y-6x-10=0
:
we need to complete the squares on the x and y terms
: adding and subtracting same terms to complete the square and to keep this an equivalent equation
: completing square
: combining terms on right
:
radius is square root of the right side in this form.
:
so the center is (3,-9/2) and the radius is
You can put this solution on YOUR website! find the center and radius of y^2+x^2+9y-6x-10=0
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Complete the square on the x-terms and on the y-terms:
[x^2 - 6x + ?] + [y^2 + 9y + ?] = 10
[x^2 -6x + 9] + [y^2 + 9y + (9/2)^2] = 10 + 9 + (9/2)^2
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(x-3)^2 + (y+(9/2))^2 = 23.5
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Center: (3,(-9/2))
Radius: sqrt(23.5)
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Cheers,
Stan H.