SOLUTION: Solve for roots 3sin^2x-8sinx-3=0

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Question 149437: Solve for roots
3sin^2x-8sinx-3=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
3%2Asin%5E2%28x%29-8%2Asin%28x%29-3=0
Let's substitute u=sin%28x%29
3u%5E2-8u-3=0 Quadratic equation in u.
%283u%2B1%29%28u-3%29=0Factor the quadratic equation.
First factor:
3u%2B1=0
3sin%28x%29%2B1=0
3sin%28x%29=-1
sin%28x%29=-1%2F3
2 solutions for this equation.
x=340.53 degrees and x=199.47 degrees
Second factor:
u-3=0
sin%28x%29-3=0
sin%28x%29=3
sin(x) is never greater than 1, so there are no additional solutions.
Below is the graph of the function.
+graph%28+300%2C+200%2C+0%2C+7%2C+-10%2C10%2C+3%2A%28sin%28x%29%5E2%29-8%2Asin%28x%29-3%29+
Note : x axis is measured in radians.
360 degrees = 6.28 radians
340.53 degrees = 5.94 radians
199.47 degrees = 3.48 radians