SOLUTION: Determine the general solution to the equation 0=2sinθ

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Question 1181871: Determine the general solution to the equation 0=2sinθ
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

given:
0=2sin%28theta%29
sin%28theta%29=0
theta=sin%5E-1%280%29
theta=0 radians
theta=0°
periodicity of sine is 2pi
general solutions:
theta=2pi%2An
theta=pi+%2B2pi%2An
Degrees:
theta=0%2B360%2An°
theta=180%2B360%2An°


Answer by ikleyn(52802) About Me  (Show Source):
You can put this solution on YOUR website!
.

Equation  0 = 2sin%28theta%29  is equivalent to  sin%28theta%29 = 0,


which has the general solution  theta = k%2Api  radians,  where k is any integer number  k = 0, +/- 1, +/- 2, . . . 



Or, in the degrees form,  theta = k*180°.



One formula (in radians or in degrees) works for all possible solutions.

Solved, and carefully explained.