SOLUTION: if sinθ=0.6157 and 90⁰<θ<360⁰, then θ, to the nearest degree, is

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Question 1181869: if sinθ=0.6157 and 90⁰<θ<360⁰, then θ, to the nearest degree, is
Found 3 solutions by greenestamps, MathLover1, ikleyn:
Answer by greenestamps(13203) About Me  (Show Source):
You can put this solution on YOUR website!


Sine is positive in quadrants I and II; the problem specifies we want an angle in quadrant II.

(1) Use a calculator to determine sin%5E%28-1%29%280.6157%29. Make sure your calculator is set to give the result in degrees and not radians.

The calculator will give you an angle x in quadrant I. The angle in quadrant II with the same value of sine is (180-x) degrees.

Angle x turns out to be very nearly a whole number of degrees, so expressing your final answer to the nearest degree will be easy.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

given:
sin%28theta%29=0.6157 and 90%3Ctheta%3C360⁰
theta=sin+%5E-1%280.6157%29
theta=0.663274...(result in radians)
theta=38°
theta=0.663274%2B2pi%2An....n=1
theta=pi+-sin%5E-1%280.6157%29%2B2pi%2B2pi=6.946459307179587
theta=398° (degrees)=> disregard, excedes given range
or
theta=pi+-sin%5E-1%280.6157%29%2B2pi%2An...n=1
theta=pi+-0.663274%2B2pi
theta=+-0.663274%2Bpi
theta=502° (degrees)

Solutions for the range 90%3Ctheta%3C360⁰:
=>no solution for theta in R

Answer by ikleyn(52810) About Me  (Show Source):
You can put this solution on YOUR website!
.

As @MathLover1 responded, she demonstrated the absence of knowledge in trigonometry basics.


Her answer is incorrect.


Use the correct answer by @greenestamps and IGNORE that by @MathLover1.