Question 1180032: Consider the angle shown below with an initial ray pointing in the 3-o'clock direction that measures θ radians (where 0≤θ<2π. The circle's radius is 2.3 units long and the terminal point is (−1.35,1.86)
a) What is the slope of the terminal ray?
m=
b) Then, tan−1(m)=
c) Does the number we get in part (b) give us the correct value of θ? ? Yes No
d) Therefore, θ=
Answer by MathLover1(20855)   (Show Source):
You can put this solution on YOUR website! The circle's radius is  units long and the terminal point is ( , )
the point (,) is in Q II and tan is negative
Since the position in the 3-o'clock is basically the positive x-axis, this means the angle that is terminating at ( , ) (which is in Q IV) should look like:
sketch
Notice that we can draw a right triangle by drawing a vertical straight line from the point (,).
from the right triangle we have
a) What is the slope of the terminal ray?
b) Then,  °
c) Does the number we get in part (b) give us the correct value of  ?
d) Therefore, since the point (,) is in Q II,
we then subtract it from  because the coordinates of the point (,) are in the 4th quadrant, we need angle in Q II
 °
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