SOLUTION: Find all solutions to sin^-1(1/2) between 0 degrees and 360 degrees. (I know that 30 degrees is a solution, but I'm not sure if there are anymore)
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Question 1174709: Find all solutions to sin^-1(1/2) between 0 degrees and 360 degrees. (I know that 30 degrees is a solution, but I'm not sure if there are anymore) Found 2 solutions by Theo, AnlytcPhil:Answer by Theo(13342) (Show Source):
the sine function is positive in the first and second quadrant.
the sine function is negative in the third and fourth quadrants.
the equivalent angle in the second quadrant is 180 - 30 = 150 degrees.
the equivalent angle in the third quadrant is 180 + 30 = 210 degrees.
the equivalent angle in the fourth quadrant is 360 - 30 = 330 degrees.
all of these angles have the same value of sine, except for the sign.
That's wrong.
Since we want inverse trig functions to be functions, they must always
have a unique value, so the rule that's chosen by mathematicians is:
Inverse sine, cosine and tangent functions are restricted so that they can only
be the smallest possible angle in absolute value, and if that results in a choice
between a positive or a negative angle, the positive angle is chosen.
So sin-1(1/2) = 30°
All other angles which have sine equaling 1/2 are larger in absolute value than
30°, so 30° is the only answer.
Edwin