SOLUTION: hello pls help solve" S16 for $200+$200(1.06)+$200+(1.06)^2+...

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Question 1163029: hello pls help solve"
S16 for $200+$200(1.06)+$200+(1.06)^2+...
Found 2 solutions by greenestamps, ikleyn:
Answer by greenestamps(13206) About Me  (Show Source):
You can put this solution on YOUR website!


S16 = 200 + 200(1.06) + ... + 200(1.06)^15

S%28n%29+=+a%281%29%28%281-r%5En%29%2F%281-r%29%29

S%2816%29+=+200%28%281-1.06%5E16%29%2F%281-1.06%29%29

Use a calculator....

Note $200*16 = $3200, so your answer should be somewhere around $4000 to $5000; if not, you didn't do the calculation correctly.

Answer by ikleyn(52866) About Me  (Show Source):
You can put this solution on YOUR website!
.

S16 = 200 + 200(1.06) + ... + 200(1.06)^15

S%28n%29 = a%281%29%2A%28%281-r%5En%29%2F%281-r%29%29                 <<<---<<< notice the degree index in the numerator (!)

S%2816%29 = 200%2A%28%281-1.06%5E16%29%2F%281-1.06%29%29 = 5134.506     (approximately)         ANSWER

Solved.

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On geometric progressions,  see introductory lessons
    - Geometric progressions
    - The proofs of the formulas for geometric progressions
    - Problems on geometric progressions
    - Word problems on geometric progressions
in this site.

Also,  you have this free of charge online textbook in ALGEBRA-II in this site
    - ALGEBRA-II - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic
"Geometric progressions".

Save the link to this textbook together with its description

Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson

into your archive and use when it is needed.


See also this Wikipedia article
https://en.wikipedia.org/wiki/Geometric_series
https://en.wikipedia.org/wiki/Geometric_series