SOLUTION: Express sin 485° in terms of its reference angle. Show work.

Algebra ->  Trigonometry-basics -> SOLUTION: Express sin 485° in terms of its reference angle. Show work.      Log On


   

Question 1138398: Express sin 485° in terms of its reference angle. Show work.
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Express sin%28485%29° in terms of its reference angle. Show work
485° is equal to 360%2B125°; so, you look for 125° which is in Q II
note:
A reference angle is an angle whose measure is between 0° and+90° (not including 0° or 90°)
If theta is your angle, here’s how to find its reference angle.
Quadrant |Reference Angle
II............ | <180° - theta
III ...........|< theta - 180°
IV............| < 360° - theta

then, reference angle is:
sin%28485%29° = sin%28125%29°
reference angle: 180-125=55°
=>+sin%28485%29+=+sin%2855%29